Given a non-negative integer represented as a non-empty array of digits, plus one to the integer.
You may assume the integer do not contain any leading zero, except the number 0 itself.
The digits are stored such that the most significant digit is at the head of the list.
public class Solution { public int[] plusOne(int[] digits) { for(int i=digits.length -1; i>=0;i--){ if(digits[i] <9){ digits[i]++; return digits; } digits[i] = 0; } if(digits[0] == 0){ int[] newn = new int[digits.length+1]; newn[0] =1; return newn; } else{ return digits; } } }
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Original author:Jake Tao,source:「LeetCode – 66. Plus One」