Given a binary array, find the maximum number of consecutive 1s in this array.
Example 1:
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
Note:
- The input array will only contain
0and1. - The length of input array is a positive integer and will not exceed 10,000
public class Solution { public int findMaxConsecutiveOnes(int[] nums) { int count = 0; int result = 0; for(int i=0;i result){ result = count; } } if(nums[i] == 0){ if(count > result){ result = count; } count =0; } } return result; } } This siteOriginal articleAll follow "Attribution-NonCommercial-ShareAlike 4.0 License (CC BY-NC-SA 4.0)Please retain the following annotations when sharing or adapting:
Original author:Jake Tao,source:「LeetCode – 485. Max Consecutive Ones」