LeetCode – 485. Max Consecutive Ones

Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

Input:  [1,1,0,1,1,1]  Output: 3 Explanation:  The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.  

Note:

  • The input array will only contain 0 and 1.
  • The length of input array is a positive integer and will not exceed 10,000
public class Solution { public int findMaxConsecutiveOnes(int[] nums) { int count = 0; int result = 0; for(int i=0;i result){ result = count; } } if(nums[i] == 0){ if(count > result){ result = count; } count =0; } } return result; } }

This siteOriginal articleAll follow "Attribution-NonCommercial-ShareAlike 4.0 License (CC BY-NC-SA 4.0)Please retain the following annotations when sharing or adapting:

Original author:Jake Tao,source:「LeetCode – 485. Max Consecutive Ones」

130
0 0 130

Further Reading

Post a reply

Log inYou can only comment after that.
Share this page
Back to top