Given a linked list, determine if it has a cycle in it.
Follow up:
Can you solve it without using extra space?
用两个指针,一快一慢,如果有cycle肯定会交汇
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public boolean hasCycle(ListNode head) {
if(head == null) return false;
ListNode slow = head;
ListNode fast = head;
while(fast.next != null && fast.next.next != null){
slow =slow.next;
fast = fast.next.next;
if(slow == fast){
return true;
}
}
return false;
}
}
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Original author: Jake Tao Source: 「LeetCode – 141. Linked List Cycle」
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