Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.
For example:
Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
class Solution {
public int addDigits(int num) {
while(num >= 10){
num = num/10 + num%10;
}
return num;
}
}
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原文来源：《258. Add Digits》
